MybatisPlus学习〖三〗
我们继续学习mp的增删改查接口
代码具体的实现
条件构造器实现
1. 查询user表中user_name字段模糊查询’张’,或者user_age年龄大于20岁,按照user_age降序排列,年龄相同的就按照id升序排列
@Test
public void select_1_ByWrapper(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.like("user_name","张").or().ge("user_age",20).orderByDesc("user_age").orderByAsc("id");
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
利用条件构造器来拼接SQL语句
- like() : SQL里的like字段
- or() : 实现拼接一个简单的or字段在SQL语句里面
- ge() : 实现拼接一个">=",第一个字段指定数据库字段名称,第二个代表值
- orderByDesc/orderByAsc() : 在语句中拼接orderbyDesc/orderByAsc语句
查询结果如下
mp已经自动帮我们拼接好了SQL语句并查询出记录
2.查询user表中姓名有张,或者年龄小于30大于18且email不为空的用户
@Test
public void select_2_ByWrapper(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.likeRight("user_name","张").or(wq->wq.lt("user_age",30).gt("user_age",18).isNotNull("user_email"));
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
相同的方法就不再一一列举,这里只列举未出现的方法的意思
- likeRight : 相当于like 'xx%'在右边拼接%,likeLeft就是在参数左边拼接%
- gt : 实现拼接>符号,第一个参数为数据库字段,第二个为>参数
- isNotNull : 实现拼接xx参数is not null语句
输出目录,果然已经拼接上去,这里的or()实现了把后面字段加进括号内的Lambda表达式来实现
DEBUG==> Preparing: SELECT id,user_phone,user_email,user_name,user_age FROM user WHERE (user_name LIKE ? OR ( (user_age < ? AND user_age > ? AND user_email IS NOT NULL) ))
DEBUG==> Parameters: 张%(String), 30(Integer), 18(Integer)
TRACE<== Columns: id, user_phone, user_email, user_name, user_age
TRACE<== Row: 2, 15336155900, dsadas@qq.com, 乔佳, 20
TRACE<== Row: 3, 1312312312312, aiqianqian1@qq.com, 张倩, 27
TRACE<== Row: 4, 1312312312312, aikaikai@qq.com, 张倩, 25
TRACE<== Row: 5, 1312312312312, , 张倩111, 18
DEBUG<== Total: 4
3.查询(年龄小于30或者email不为空)且名字有张的用户信息
@Test
public void select_3_ByWrapper(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.nested(qw->qw.lt("user_age",30).or().isNotNull("user_email")).likeRight("user_name","张");
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
- lt : 拼接小于符号
- nested : 实现一开始拼接()里面使用Lambda表达式来实现
输出目录如下,SQL语句实现了先拼接()在拼接AND user_name LIKE…
DEBUG==> Preparing: SELECT id,user_phone,user_email,user_name,user_age FROM user WHERE (( (user_age < ? OR user_email IS NOT NULL) ) AND user_name LIKE ?)
DEBUG==> Parameters: 30(Integer), 张%(String)
TRACE<== Columns: id, user_phone, user_email, user_name, user_age
TRACE<== Row: 3, 1312312312312, aiqianqian1@qq.com, 张倩, 27
TRACE<== Row: 4, 1312312312312, aikaikai@qq.com, 张倩, 25
TRACE<== Row: 5, 1312312312312, , 张倩111, 18
DEBUG<== Total: 3
4.查询指定字段并且用户年龄在指定年龄中
@Test
public void select_4_ByWrapper(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.select("user_name","user_age","user_email").in("user_age", Arrays.asList(20,6,30,15));
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
- select : 实现查询指定字段的记录,参数为数据库字段名
- in : 实现了拼接in(x,x,x…),第一个参数为数据库字段名,第二个参数为一个list包含in里面的内容
输出目录如下,SQL语句实现了查询指定字段并且in(x,x,x…)的记录
DEBUG==> Preparing: SELECT user_name,user_age,user_email FROM user WHERE (user_age IN (?,?,?,?))
DEBUG==> Parameters: 20(Integer), 6(Integer), 30(Integer), 15(Integer)
TRACE<== Columns: user_name, user_age, user_email
TRACE<== Row: 乔佳, 20, dsadas@qq.com
DEBUG<== Total: 1
5.查询不为空的字段加进查询子句中
@Test
public void select_5_ByWrapper(){
String name="王";
String age="";
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.like(StringUtils.isNotEmpty(name),"user_name",name).like(StringUtils.isNotEmpty(age),"user_age",age);
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
- like : 可以实现带三个参数的方法,第一个参数若为false就不加指定字段的内容
输出目录如下,SQL语句实现了将不为空的字段加进like语句里面
DEBUG==> Preparing: SELECT id,user_phone,user_email,user_name,user_age FROM user WHERE (user_name LIKE ?)
DEBUG==> Parameters: %王%(String)
TRACE<== Columns: id, user_phone, user_email, user_name, user_age
TRACE<== Row: 1, 17729020601, 155019@qq.com, 王凯艺, 10
DEBUG<== Total: 1
6.通过实体类查询实体类有的字段的信息
@Test
public void select_6_ByWrapper(){
UserDO userDO=new UserDO();
userDO.setUserAge(20);
userDO.setUserName("张倩");
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>(userDO);
List<UserDO> userDOList=userDOMapper.selectList(queryWrapper);
}
- 这里我们直接构造了一个对象,将对象传进去,拼接里面不为空的字段到where中,实现查询
DEBUG==> Preparing: SELECT id,user_phone,user_email,user_name,user_age FROM user WHERE user_name=? AND user_age=?
DEBUG==> Parameters: 张倩(String), 20(Integer)
DEBUG<== Total: 0
7.通过selectMap的方式返回一个map查询你想要的字段信息
@Test
public void select_7_ByWrapperByMaps(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.select("user_name","user_phone").like("user_name","张").eq("user_age",18);
List<Map<String,Object>> userDOList=userDOMapper.selectMaps(queryWrapper);
}
- eq : 拼接=符号,第一个参数为数据库字段,第二个参数为拼接=后的内容
- selectMaps : 这里使用了map来传递查询指定字段记录,其余字段并不显示
输出日志如下,结果为Map的两个字段的内容
DEBUG==> Preparing: SELECT user_name,user_phone FROM user WHERE (user_name LIKE ? AND user_age = ?)
DEBUG==> Parameters: %张%(String), 18(Integer)
TRACE<== Columns: user_name, user_phone
TRACE<== Row: 张倩111, 1312312312312
DEBUG<== Total: 1
8.查询在查询条件下的返回记录数
@Test
public void select_8_ByWrapperCount(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.like("user_name","张").le("user_age",30);
Integer count=userDOMapper.selectCount(queryWrapper);
System.out.println("总记录数: "+count);
}
- le : 拼接<=符号,数据库字段+参数内容
- selectCount : 使用查询记录的方法,返回一个查询的记录数
输出日志如下,返回一个记录数
DEBUG==> Preparing: SELECT COUNT( 1 ) FROM user WHERE (user_name LIKE ? AND user_age <= ?)
DEBUG==> Parameters: %张%(String), 30(Integer)
TRACE<== Columns: COUNT( 1 )
TRACE<== Row: 3
DEBUG<== Total: 1
总记录数: 3
9.lambda表达式拼接语句防误写
@Test
public void select_9_Lambda(){
LambdaQueryWrapper<UserDO> queryWrapper = new QueryWrapper<UserDO>().lambda();
queryWrapper.select(UserDO::getId).like(UserDO::getUserName,"张").le(UserDO::getUserAge,30);
List<UserDO> list=userDOMapper.selectList(queryWrapper);
}
- new QueryWrapper().lambda() : 这里使用lambda()方法来实现lambda表达式
- select : (类名:: 参数)来实现 select(“数据库的字段名”)一样的方法
输出日志如下,这里使用lambda表达式来防误写数据库字段
DEBUG==> Preparing: SELECT id FROM user WHERE (user_name LIKE ? AND user_age <= ?)
DEBUG==> Parameters: %张%(String), 30(Integer)
TRACE<== Columns: id
TRACE<== Row: 3
TRACE<== Row: 4
TRACE<== Row: 5
DEBUG<== Total: 3
10.实现分页查询查询在条件下若每页显示2条记录,显示第一页的记录
分页查询
@Test
public void select_10_Page(){
QueryWrapper<UserDO> queryWrapper=new QueryWrapper<>();
queryWrapper.le("user_age",30);
Page<UserDO> page=new Page<>(1,2);
IPage<UserDO> iPage=userDOMapper.selectPage(page,queryWrapper);
System.out.println("总页数: "+iPage.getPages());
System.out.println("总记录数: "+iPage.getTotal());
List<UserDO> records = iPage.getRecords();
// 引用输出 records.forEach(System.out::println);
records.forEach(l-> System.out.println(l));
}
- new Page<>(1,2) : 第一个参数为第几页,第二个参数为一页显示的数量
- selectPage : 实现分页查询,第一个参数为设置好的page对象,第二个参数为构造器内容
输出日志如下,这里我们输出了总页数与总记录
DEBUG==> Preparing: SELECT COUNT(1) FROM user WHERE (user_age <= ?)
DEBUG==> Parameters: 30(Integer)
TRACE<== Columns: COUNT(1)
TRACE<== Row: 5
DEBUG==> Preparing: SELECT id,user_phone,user_email,user_name,user_age FROM user WHERE (user_age <= ?) LIMIT ?,?
DEBUG==> Parameters: 30(Integer), 0(Long), 2(Long)
TRACE<== Columns: id, user_phone, user_email, user_name, user_age
TRACE<== Row: 1, 17729020601, 155019@qq.com, 王凯艺, 10
TRACE<== Row: 2, 15336155900, dsadas@qq.com, 乔佳, 20
DEBUG<== Total: 2
总页数: 3
总记录数: 5
UserDO(id=1, userName=王凯艺, userPhone=17729020601, userAge=10, userEmail=155019@qq.com)
UserDO(id=2, userName=乔佳, userPhone=15336155900, userAge=20, userEmail=dsadas@qq.com)
11.根据id更新用户信息
@Test
public void select_11_updateById(){
UserDO userDO=new UserDO();
userDO.setId(4);
userDO.setUserAge(25);
userDO.setUserEmail("aikaikai@qq.com");
int rows=userDOMapper.updateById(userDO);
System.out.println("影响了: "+rows+" 行");
}
- updateById : 这里我们传入一个实体类对象,根据id来更新实体类里存在的字段名称,返回一个影响的记录数
DEBUG==> Preparing: UPDATE user SET user_email=?, user_age=? WHERE id=?
DEBUG==> Parameters: aikaikai@qq.com(String), 25(Integer), 4(Integer)
DEBUG<== Updates: 1
影响了: 1 行
12.更新用户年龄和邮箱被更新用户信息为张倩,邮箱为qianqian@qq.com
@Test
public void select_12_update(){
UpdateWrapper<UserDO> userDOUpdateWrapper=new UpdateWrapper<>();
userDOUpdateWrapper.eq("user_name","张倩").eq("user_email","qianqian@qq.com");
UserDO userDO=new UserDO();
userDO.setUserAge(26);
userDO.setUserEmail("aiqianqian@qq.com");
int rows=userDOMapper.update(userDO,userDOUpdateWrapper);
System.out.println("影响记录数: "+rows);
}
- new UpdateWrapper<>() : 这里使用这个构造方法来拼接where后的sql语句
- update() : 这个方法有两个参数,第一个参数传入一个实体类,包含实体类里有的字段都会更新,第二个参数使用构造器来拼接where后的字段
输出日志如下,这里我们输出了update方法
DEBUG==> Preparing: UPDATE user SET user_email=?, user_age=? WHERE (user_name = ? AND user_email = ?)
DEBUG==> Parameters: aiqianqian@qq.com(String), 26(Integer), 张倩(String), qianqian@qq.com(String)
DEBUG<== Updates: 0
影响记录数: 0
13.当更新少数字段的时候可以用set方法
@Test
public void select_13_update(){
UpdateWrapper<UserDO> userDOUpdateWrapper=new UpdateWrapper<>();
userDOUpdateWrapper.eq("user_name","张倩").eq("user_email","aiqianqian@qq.com").set("user_age",27);
int rows=userDOMapper.update(null,userDOUpdateWrapper);
System.out.println("影响记录数: "+rows);
}
- set : 使用这个方法可以使更新少数字段更为简便,数据库字段名+参数
输出日志如下,这里我们我们的update跟的第一个参数实体类我们要设置为空才可以
DEBUG==> Preparing: UPDATE user SET user_age=? WHERE (user_name = ? AND user_email = ?)
DEBUG==> Parameters: 27(Integer), 张倩(String), aiqianqian@qq.com(String)
DEBUG<== Updates: 0
影响记录数: 0
14.Lambda表达式更新用户信息
@Test
public void select_14_updateLambda(){
LambdaUpdateWrapper<UserDO> updateWrapper = new UpdateWrapper<UserDO>().lambda();
updateWrapper.eq(UserDO::getUserName,"张倩").eq(UserDO::getUserAge,27).set(UserDO::getUserEmail,"aiqianqian1@qq.com");
int rows=userDOMapper.update(null,updateWrapper);
System.out.println("影响记录数: "+rows);
}
这里我们跟之前lambda表达式一样,引用(类名::方法名)就可以指定数据库字段
DEBUG==> Preparing: UPDATE user SET user_email=? WHERE (user_name = ? AND user_age = ?)
DEBUG==> Parameters: aiqianqian1@qq.com(String), 张倩(String), 27(Integer)
DEBUG<== Updates: 1
影响记录数: 1
15.根据id删除信息返回删除条数
@Test
public void select_15_deleteById(){`在这里插入代码片`
int rows=userDOMapper.deleteById(6);
System.out.println("删除条数 :"+rows+" 条");
}
- deleteById : 删除指定id记录,返回删除的记录数
DEBUG==> Preparing: DELETE FROM user WHERE id=?
DEBUG==> Parameters: 6(Integer)
DEBUG<== Updates: 0
删除条数 :0 条
16.根据map设置进去的参数删除符合条件的记录
@Test
public void select_16_deleteByMap(){
Map<String,Object> map=new HashMap<>();
map.put("user_name","测试");
map.put("user_age",25);
int rows=userDOMapper.deleteByMap(map);
System.out.println("删除条数 :"+rows+" 条");
// 下一个方法是批量删除id为list里的记录,返回删除记录数
// int row=userDOMapper.deleteBatchIds(Arrays.asList(7));
}
- deleteByMap : 根据map里面的字段来删除指定记录,返回了一个删除记录数
输出日志如下,这里输出了删除语句
DEBUG==> Preparing: DELETE FROM user WHERE user_name = ? AND user_age = ?
DEBUG==> Parameters: 测试(String), 25(Integer)
DEBUG<== Updates: 0
删除条数 :0 条
17.Lambda表达式拼接删除语句
@Test
public void select_17_deleteLambda(){
LambdaQueryWrapper<UserDO> queryWrapper = new QueryWrapper<UserDO>().lambda();
queryWrapper.eq(UserDO::getUserName,"测试").eq(UserDO::getUserAge,15);
int rows=userDOMapper.delete(queryWrapper);
System.out.println("删除条数 :"+rows+" 条");
}
输出日志如下,这里运用了lambda表达式拼接SQL语句,返回一个删除记录数
DEBUG==> Preparing: DELETE FROM user WHERE (user_name = ? AND user_age = ?)
DEBUG==> Parameters: 测试(String), 15(Integer)
DEBUG<== Updates: 0
删除条数 :0 条
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转载:https://blog.csdn.net/kingtok/article/details/102467347