一、处理丢失数据
Pandas 使用 numpy.NaN 来表示丢失的数据，它不参与计算。
import pandas as pd
import numpy as np
dates = pd.date_range('20160301', periods=6)
df = pd.DataFrame(data=np.random.randn(6, 4), index=dates, columns=list('ABCD'))
df
>>>
A B C D
2016-03-01 -0.768789 1.347539 0.715367 0.581275
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110
2016-03-03 0.815005 -0.343642 2.097537 1.706366
2016-03-04 0.755148 0.022449 -0.033679 -0.411535
2016-03-05 1.361040 -0.813593 -1.230564 -0.957386
2016-03-06 0.277162 -0.650544 -0.152688 1.070919
- 添加新的列
df1 = df.reindex(index=dates[0:4], columns=list(df.columns) + ['E'])
df1
>>>
A B C D E
2016-03-01 -0.768789 1.347539 0.715367 0.581275 NaN
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110 NaN
2016-03-03 0.815005 -0.343642 2.097537 1.706366 NaN
2016-03-04 0.755148 0.022449 -0.033679 -0.411535 NaN
1.为空值数据赋值
df1.loc[dates[1:3], 'E'] = 1
df1
>>>
A B C D E
2016-03-01 -0.768789 1.347539 0.715367 0.581275 NaN
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110 1.0
2016-03-03 0.815005 -0.343642 2.097537 1.706366 1.0
2016-03-04 0.755148 0.022449 -0.033679 -0.411535 NaN
还可以这样做：
df1.loc['20160302':'20160303','E']=5
2.删除空数据行和列
不会改变df1的结构和数据
df1.dropna(how='any')
>>>
A B C D E
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110 1.0
2016-03-03 0.815005 -0.343642 2.097537 1.706366 1.0
可以通过axis参数来删除含有空数据的全部列
df1 = df1.dropna(axis=1)
可以通过subset参数来删除E中含有空数据的全部行
df1 = df1.dropna(subset=["E"])
3.填充所有缺失数据
同样不改变df1的数据和结构
df1.fillna(value=5)
>>>
A B C D E
2016-03-01 -0.768789 1.347539 0.715367 0.581275 5.0
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110 1.0
2016-03-03 0.815005 -0.343642 2.097537 1.706366 1.0
2016-03-04 0.755148 0.022449 -0.033679 -0.411535 5.0
4.判断是否有NaN值
NaN, Not a Number, NaN是浮点数的一个值，代表“不是数”. 它即不是无穷大, 也不是无穷小.
存在NaN，返回True
pd.isnull(df1)
>>>
A B C D E
2016-03-01 False False False False True
2016-03-02 False False False False False
2016-03-03 False False False False False
2016-03-04 False False False False True
二、统计
numpy.NaN 不参与计算
1.平均值、求和、累加和
df1.mean() #默认按列求平均值
df1.mean(axis=1) #按行求平均值
df.sum() #按列求和
df.sum(axis='columns') #按行求和
df.cumsum() #计算轴向元素累加和,返回由中间结果组成的数组
2.shift函数
该函数主要的功能就是使数据框中的数据移动，若freq=None时，根据axis的设置，行索引数据保持不变，列索引数据可以在行上上下移动或在列上左右移动；若行索引为时间序列，则可以设置freq参数，根据periods和freq参数值组合，使行索引每次发生periods*freq偏移量滚动，列索引数据不会移动
# shift(0)
s = pd.Series([1,3,5,np.nan,6,8], index=dates).shift(0)
s
>>>
2020-04-29 1.0
2020-04-30 3.0
2020-05-01 5.0
2020-05-02 NaN
2020-05-03 6.0
2020-05-04 8.0
Freq: D, dtype: float64
#shift(1)
s = pd.Series([1,3,5,np.nan,6,8], index=dates).shift(1)
s
>>>
2020-04-29 NaN
2020-04-30 1.0
2020-05-01 3.0
2020-05-02 5.0
2020-05-03 NaN
2020-05-04 6.0
Freq: D, dtype: float64
3.sub函数
>>> df
A B C D
2016-03-01 -0.768789 1.347539 0.715367 0.581275
2016-03-02 0.163001 -0.509262 -0.615675 -0.220110
2016-03-03 0.815005 -0.343642 2.097537 1.706366
2016-03-04 0.755148 0.022449 -0.033679 -0.411535
2016-03-05 1.361040 -0.813593 -1.230564 -0.957386
2016-03-06 0.277162 -0.650544 -0.152688 1.070919
>>> s
2016-03-01 NaN
2016-03-02 1.0
2016-03-03 3.0
2016-03-04 5.0
2016-03-05 NaN
2016-03-06 6.0
Freq: D, dtype: float64
- sub减法，二维数组
df按行减去一维数组s的值
>>> df.sub(s,axis='index')
A B C D
2016-03-01 NaN NaN NaN NaN
2016-03-02 -0.836999 -1.509262 -1.615675 -1.220110
2016-03-03 -2.184995 -3.343642 -0.902463 -1.293634
2016-03-04 -4.244852 -4.977551 -5.033679 -5.411535
2016-03-05 NaN NaN NaN NaN
2016-03-06 -5.722838 -6.650544 -6.152688 -4.929081
4.apply 应用函数
- 使用apply函数，调用cumsum函数
df.apply(np.cumsum)
>>>
A B C D
2016-03-01 -0.768789 1.347539 0.715367 0.581275
2016-03-02 -0.605788 0.838277 0.099692 0.361166
2016-03-03 0.209217 0.494635 2.197229 2.067531
2016-03-04 0.964365 0.517084 2.163549 1.655996
2016-03-05 2.325405 -0.296509 0.932986 0.698610
2016-03-06 2.602567 -0.947053 0.780298 1.769529
- 使用apply函数，自定义一个函数，返回每列最大值与最小值的差值
df.apply(lambda x: x.max() - x.min())
>>>
>>> df.apply(lambda x: x.max() - x.min())
A 2.129829
B 2.161131
C 3.328100
D 2.663752
dtype: float64
- 返回每行最大值与最小值的差值
df.apply(lambda x: x.max() - x.min() ,axis=1)
5.计数和众数
s = pd.Series(np.random.randint(0, 7, size=10))
s
>>>
0 4
1 6
2 6
3 0
4 5
5 4
6 6
7 4
8 1
9 1
计数，每个数字出现的次数
>>> s.value_counts()
6 3
4 3
1 2
5 1
0 1
dtype: int64
众数，4和6出现的次数最多
>>> s.mode()
0 4
1 6
三、数据合并
1.concat函数
>>> df = pd.DataFrame(np.random.randn(10, 4), columns=list('ABCD'))
>>> df
A B C D
0 -0.650238 1.293171 1.091541 0.178952
1 -0.164027 -0.053264 0.490023 -0.992589
2 0.782788 0.254571 -1.867243 0.529259
3 -0.429579 0.562526 -0.436258 2.364229
4 2.234823 -1.420623 -0.809523 0.165442
5 -0.277173 -0.151315 -0.132357 -0.992252
6 0.261993 0.018131 1.355897 0.151521
7 -0.696561 -2.785051 -0.771156 0.278054
8 0.995268 0.083372 -0.498132 0.946659
9 0.675779 -0.853811 -0.674370 -1.470860
>>> df.iloc[:3]
A B C D
0 -0.650238 1.293171 1.091541 0.178952
1 -0.164027 -0.053264 0.490023 -0.992589
2 0.782788 0.254571 -1.867243 0.529259
>>> df.iloc[3:7]
A B C D
3 -0.429579 0.562526 -0.436258 2.364229
4 2.234823 -1.420623 -0.809523 0.165442
5 -0.277173 -0.151315 -0.132357 -0.992252
6 0.261993 0.018131 1.355897 0.151521
>>> df.iloc[7:]
A B C D
7 -0.696561 -2.785051 -0.771156 0.278054
8 0.995268 0.083372 -0.498132 0.946659
9 0.675779 -0.853811 -0.674370 -1.470860
- concat函数
df1 = pd.concat([df.iloc[:3], df.iloc[3:7], df.iloc[7:]])
df1
>>> df1 = pd.concat([df.iloc[:3], df.iloc[3:7], df.iloc[7:]])
>>> df1
A B C D
0 -0.650238 1.293171 1.091541 0.178952
1 -0.164027 -0.053264 0.490023 -0.992589
2 0.782788 0.254571 -1.867243 0.529259
3 -0.429579 0.562526 -0.436258 2.364229
4 2.234823 -1.420623 -0.809523 0.165442
5 -0.277173 -0.151315 -0.132357 -0.992252
6 0.261993 0.018131 1.355897 0.151521
7 -0.696561 -2.785051 -0.771156 0.278054
8 0.995268 0.083372 -0.498132 0.946659
9 0.675779 -0.853811 -0.674370 -1.470860
2.SQL 样式的联合查询（merge函数）
>>> left = pd.DataFrame({'key': ['foo', 'foo'], 'lval': [1, 2]})
>>> right = pd.DataFrame({'key': ['foo', 'foo'], 'rval': [4, 5]})
>>> left
key lval
0 foo 1
1 foo 2
>>> right
key rval
0 foo 4
1 foo 5
merge合并
# SELECT * FROM left INNER JOIN right ON left.key = right.key;
pd.merge(left, right, on='key')
>>>
key lval rval
0 foo 1 4
1 foo 1 5
2 foo 2 4
3 foo 2 5
3.append函数
append是series和dataframe的方法，使用它就是默认沿着（axis = 0）列进行拼接
>>> s = pd.Series(np.random.randint(1, 5, size=4), index=list('ABCD'))
>>> df.append(s, ignore_index=True)
A B C D
0 -0.650238 1.293171 1.091541 0.178952
1 -0.164027 -0.053264 0.490023 -0.992589
2 0.782788 0.254571 -1.867243 0.529259
3 -0.429579 0.562526 -0.436258 2.364229
4 2.234823 -1.420623 -0.809523 0.165442
5 -0.277173 -0.151315 -0.132357 -0.992252
6 0.261993 0.018131 1.355897 0.151521
7 -0.696561 -2.785051 -0.771156 0.278054
8 0.995268 0.083372 -0.498132 0.946659
9 0.675779 -0.853811 -0.674370 -1.470860
10 2.000000 2.000000 4.000000 2.000000
四、分组统计
- 数据分组
- 每个组应用一个函数，输出一个结果
- 合并每个组的结果构成最终输出
df = pd.DataFrame({'A' : ['foo', 'bar', 'foo', 'bar',
'foo', 'bar', 'foo', 'foo'],
'B' : ['one', 'one', 'two', 'three',
'two', 'two', 'one', 'three'],
'C' : np.random.randn(8),
'D' : np.random.randn(8)})
df
>>>
A B C D
0 foo one -0.907531 0.245216
1 bar one 0.575741 0.917884
2 foo two -0.725860 1.146291
3 bar three -0.421367 -0.885779
4 foo two -0.363707 -1.905409
5 bar two -1.307323 1.316524
6 foo one 0.436804 1.164812
7 foo three -1.146570 2.534074
- 以
‘A’为分组对象，对其他项按分组求和
>>> df.groupby('A').sum()
C D
A
bar -1.152949 1.348629
foo -2.706864 3.184985
- 以
‘A、B’为分组对象，对其他项按分组求和
# df.groupby(['B', 'A']).sum()
df.groupby(['A', 'B']).sum()
>>>
C D
A B
bar one 0.575741 0.917884
three -0.421367 -0.885779
two -1.307323 1.316524
foo one -0.470727 1.410028
three -1.146570 2.534074
two -1.089567 -0.759117
转载：https://blog.csdn.net/muguangjingkong/article/details/105890555
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